Rotation and Rolling

Weixin Image_20261014151324_137_2

Weixin Image_20261014151326_138_2

Angular Kinematics

  • Angular Variables:
    • Radians: θ\theta
    • Displacement: Δθ\Delta\theta
    • Velocity: ω\omega
    • Acceleration: α\alpha

Constant Acceleration

For an object undergoing constant angular acceleration, the linear accelerations are:

  • Tangential acceleration: at=αra_t = \alpha r
  • Centripetal acceleration: an=v2r=ω2ra_n = \frac{v^2}{r} = \omega^2 r

Rotational Dynamics

Kinetic Energy and Rotational Inertia

The kinetic energy of a rotating rigid body is derived by summing the kinetic energies of its constituent particles:

K=∑12mi(riω)2=12(∑miri2)ω2=12Iω2K = \sum \frac{1}{2} m_i (r_i \omega)^2 = \frac{1}{2} \left( \sum m_i r_i^2 \right) \omega^2 = \frac{1}{2} I \omega^2

Rotational Inertia (Moment of Inertia):

I=∑miri2I = \sum m_i r_i^2

The Parallel-Axis Theorem

For a rigid body of total mass MM rotating about an axis parallel to an axis passing through its center of mass (COM) at a distance hh:

I=Icom+Mh2I = I_{\text{com}} + Mh^2

Rolling Motion

Rolling motion can be decomposed as a combination of Translation and Rotation.

  • Velocity of center of mass: vcom=ωRv_{\text{com}} = \omega R
  • Acceleration of center of mass: acom=αRa_{\text{com}} = \alpha R

For Smooth Rolling, the velocity of a particle ii on the object is:

vi=vcom+(riω)θ^iv_i = v_{\text{com}} + (r_i \omega) \hat{\theta}_i

The total kinetic energy of a rolling object is the sum of its translational and rotational kinetic energies:

K=12Icomω2+12Mvcom2K = \frac{1}{2} I_{\text{com}} \omega^2 + \frac{1}{2} M v_{\text{com}}^2

Rolling on a Ramp

For an object rolling down an incline of angle θ\theta, the acceleration of its center of mass is:

acom=−gsin⁡θ1+IcommR2a_{\text{com}} = - \frac{g \sin \theta}{1 + \frac{I_{\text{com}}}{m R^2}}

Torque

Torque is the rotational equivalent of force on an object.

τ⃗=r⃗×F⃗=rFsin⁡ϕ\vec{\tau} = \vec{r} \times \vec{F} = r F \sin \phi

  • Moment arm: r⃗\vec{r}
  • Line of action: the line along the force vector F⃗\vec{F}

Newton’s Second Law for Rotation

The net torque on a system is equal to the rate of change of its angular momentum:

τ⃗net=dL⃗dt=Iα\vec{\tau}_{\text{net}} = \frac{d\vec{L}}{dt} = I \alpha

This relation holds when II is a constant.

Angular Momentum

  • For a single particle:

    l⃗=r⃗×p⃗=m(r⃗×v⃗)\vec{l} = \vec{r} \times \vec{p} = m (\vec{r} \times \vec{v})

  • For a system:

    L⃗=∑l⃗=Iω\vec{L} = \sum \vec{l} = I \omega

Work, Energy, and Power in Rotation

  • Work:

    W=∫θiθfτ dθ=τ(θf−θi)=ΔK=12Iωf2−12Iωi2W = \int_{\theta_i}^{\theta_f} \tau \, d\theta = \tau (\theta_f - \theta_i) = \Delta K = \frac{1}{2} I \omega_f^2 - \frac{1}{2} I \omega_i^2

  • Power:

    P=dWdt=τωP = \frac{dW}{dt} = \tau \omega

Conservation of Angular Momentum

Law of Conservation of Angular Momentum:
If the net external torque is zero (τnet=0\tau_{\text{net}} = 0), then the total angular momentum of the system is conserved:

L⃗=constant\vec{L} = \text{constant}