观察性质 + 奇偶分类构造二分图+ 二分图匹配:0109C

本文搬运自本人高中时期CSDN博客,若图片加载不出来,可到原文查看:https://blog.csdn.net/zhangtingxiqwq/article/details/135489832

http://cplusoj.com/d/senior/p/SS240109C

通过手模可知 f(a)+2C=f(a+2C)f(a) + 2C = f(a + 2C)

于是这题很多时候要在模 2C2C 意义下讨论。

假设 ii 位置放 kk ,则 2ki+12k-i+1 位置 k+ck+c 。而在模 2C2C 意义下只有这两个位置是互相联系的。所以一个朴素思路是点对配对。

配对的贡献是容易算的。假设 i,ji,j 配对, ii 位置放 kk ,则 2ki+12k-i+1 位置为 k+ck+cjj 位置为 k+c+j(2ki+1)k+c+j-(2k-i+1) 。和 ii 同余的位为 k+xiy|k+x-i-y| ,和 jj 同余的贡献为 k+c+j(2ki+1)+xj+y|k+c+j-(2k-i+1)+x-j+y| 。显然只有 kk 是变量,于是就变成了一堆绝对值方程求最小值,显然中位数。但同时必须满足 2ki+1j(modp)2k-i+1\equiv j\pmod p

但是如何构造匹配,这就是此题的精髓了。 注意到 ii2ki+12k-i+1 奇偶性不同,然后就可以构造二分图了!

因为我们有了贡献,所以直接跑二分图最大权完美匹配即可。

1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
72
73
74
75
76
77
78
79
80
81
82
83
84
85
86
87
88
89
90
91
92
93
94
95
96
97
98
99
100
101
102
103
104
105
106
107
108
109
110
111
112
113
114
115
116
117
118
119
120
121
122
123
124
125
126
127
128
129
130
131
132
133
134
135
136
137
138
139
140
141
142
143
144
145
146
147
148
149
150
151
152
153
154
155
156
157
158
159
160
161
162
163
164
165
166
167
168
169
170
171
172
173
174
175
176
177
178
179
180
181
182
183
184
185
186
187
188
189
190
191
192
193
194
195
196
197
198
199
200
201
202
203
204
205
206
207
208
209
210
211
212
213
214
215
216
217
218
219
220
221
222
223
224
225
226
227
228
229
230
231
232
233
234
235
236
237
238
239
240
241
242
243
244
245
246
247
248
249
250
251
252
253
254
255
256
257
258
259
260
261
262
263
264
265
266
267
268
269
270
271
272
273
274
275
276
277
278
279
280
281
282
283
284
285
286
287
288
289
290
291
292
293
294
295
296
297
298
299
300
301
302
303
304
305
306
307
308
309
310
311
312
313
314
315
316
317
318
319
320
321
322
323
324
325
326
327
328
329
330
331
332
333
334
335
336
337
338
339
340
341
342
343
344
345
346
347
348
349
350
351
352
353
354
355
356
357
358
359
360
361
362
363
364
365
366
367
368
369
370
371
372
373
374
375
376
377
378
379
380
381
382
383
384
385
386
387
388
389
390
391
392
393
394
395
396
397
398
399
400
401
402
403
404
405
406
407
408
409
410
411
412
413
414
415
416
417
418
419
420
421
422
423
424
425
426
427
#include<bits/stdc++.h>
using namespace std;
#ifdef LOCAL
#define debug(...) fprintf(stdout, ##__VA_ARGS__)
#else
#define debug(...) void(0)
#endif
namespace atcoder {
namespace internal {

template <class E> struct csr {
std::vector<int> start;
std::vector<E> elist;
explicit csr(int n, const std::vector<std::pair<int, E>>& edges)
: start(n + 1), elist(edges.size()) {
for (auto e : edges) {
start[e.first + 1]++;
}
for (int i = 1; i <= n; i++) {
start[i] += start[i - 1];
}
auto counter = start;
for (auto e : edges) {
elist[counter[e.first]++] = e.second;
}
}
};

} // namespace internal
namespace internal {

template <class T> struct simple_queue {
std::vector<T> payload;
int pos = 0;
void reserve(int n) {
payload.reserve(n);
}
int size() const {
return int(payload.size()) - pos;
}
bool empty() const {
return pos == int(payload.size());
}
void push(const T& t) {
payload.push_back(t);
}
T& front() {
return payload[pos];
}
void clear() {
payload.clear();
pos = 0;
}
void pop() {
pos++;
}
};

} // namespace internal


template <class Cap, class Cost> struct mcf_graph {
public:
mcf_graph() {}
explicit mcf_graph(int n) : _n(n) {}

int add_edge(int from, int to, Cap cap, Cost cost) {
assert(0 <= from && from < _n);
assert(0 <= to && to < _n);
assert(0 <= cap);
assert(0 <= cost);
int m = int(_edges.size());
_edges.push_back({from, to, cap, 0, cost});
return m;
}

struct edge {
int from, to;
Cap cap, flow;
Cost cost;
};

edge get_edge(int i) {
int m = int(_edges.size());
assert(0 <= i && i < m);
return _edges[i];
}
std::vector<edge> edges() {
return _edges;
}

std::pair<Cap, Cost> flow(int s, int t) {
return flow(s, t, std::numeric_limits<Cap>::max());
}
std::pair<Cap, Cost> flow(int s, int t, Cap flow_limit) {
return slope(s, t, flow_limit).back();
}
std::vector<std::pair<Cap, Cost>> slope(int s, int t) {
return slope(s, t, std::numeric_limits<Cap>::max());
}
std::vector<std::pair<Cap, Cost>> slope(int s, int t, Cap flow_limit) {
assert(0 <= s && s < _n);
assert(0 <= t && t < _n);
assert(s != t);

int m = int(_edges.size());
std::vector<int> edge_idx(m);

auto g = [&]() {
std::vector<int> degree(_n), redge_idx(m);
std::vector<std::pair<int, _edge>> elist;
elist.reserve(2 * m);
for (int i = 0; i < m; i++) {
auto e = _edges[i];
edge_idx[i] = degree[e.from]++;
redge_idx[i] = degree[e.to]++;
elist.push_back({e.from, {e.to, -1, e.cap - e.flow, e.cost}});
elist.push_back({e.to, {e.from, -1, e.flow, -e.cost}});
}
auto _g = internal::csr<_edge>(_n, elist);
for (int i = 0; i < m; i++) {
auto e = _edges[i];
edge_idx[i] += _g.start[e.from];
redge_idx[i] += _g.start[e.to];
_g.elist[edge_idx[i]].rev = redge_idx[i];
_g.elist[redge_idx[i]].rev = edge_idx[i];
}
return _g;
}();

auto result = slope(g, s, t, flow_limit);

for (int i = 0; i < m; i++) {
auto e = g.elist[edge_idx[i]];
_edges[i].flow = _edges[i].cap - e.cap;
}

return result;
}

private:
int _n;
std::vector<edge> _edges;

// inside edge
struct _edge {
int to, rev;
Cap cap;
Cost cost;
};

std::vector<std::pair<Cap, Cost>> slope(internal::csr<_edge>& g,
int s,
int t,
Cap flow_limit) {
// variants (C = maxcost):
// -(n-1)C <= dual[s] <= dual[i] <= dual[t] = 0
// reduced cost (= e.cost + dual[e.from] - dual[e.to]) >= 0 for all edge

// dual_dist[i] = (dual[i], dist[i])
std::vector<std::pair<Cost, Cost>> dual_dist(_n);
std::vector<int> prev_e(_n);
std::vector<bool> vis(_n);
struct Q {
Cost key;
int to;
bool operator<(Q r) const {
return key > r.key;
}
};
std::vector<int> que_min;
std::vector<Q> que;
auto dual_ref = [&]() {
for (int i = 0; i < _n; i++) {
dual_dist[i].second = std::numeric_limits<Cost>::max();
}
std::fill(vis.begin(), vis.end(), false);
que_min.clear();
que.clear();

// que[0..heap_r) was heapified
size_t heap_r = 0;

dual_dist[s].second = 0;
que_min.push_back(s);
while (!que_min.empty() || !que.empty()) {
int v;
if (!que_min.empty()) {
v = que_min.back();
que_min.pop_back();
} else {
while (heap_r < que.size()) {
heap_r++;
std::push_heap(que.begin(), que.begin() + heap_r);
}
v = que.front().to;
std::pop_heap(que.begin(), que.end());
que.pop_back();
heap_r--;
}
if (vis[v]) continue;
vis[v] = true;
if (v == t) break;
// dist[v] = shortest(s, v) + dual[s] - dual[v]
// dist[v] >= 0 (all reduced cost are positive)
// dist[v] <= (n-1)C
Cost dual_v = dual_dist[v].first, dist_v = dual_dist[v].second;
for (int i = g.start[v]; i < g.start[v + 1]; i++) {
auto e = g.elist[i];
if (!e.cap) continue;
// |-dual[e.to] + dual[v]| <= (n-1)C
// cost <= C - -(n-1)C + 0 = nC
Cost cost = e.cost - dual_dist[e.to].first + dual_v;
if (dual_dist[e.to].second - dist_v > cost) {
Cost dist_to = dist_v + cost;
dual_dist[e.to].second = dist_to;
prev_e[e.to] = e.rev;
if (dist_to == dist_v) {
que_min.push_back(e.to);
} else {
que.push_back(Q {dist_to, e.to});
}
}
}
}
if (!vis[t]) {
return false;
}

for (int v = 0; v < _n; v++) {
if (!vis[v]) continue;
// dual[v] = dual[v] - dist[t] + dist[v]
// = dual[v] - (shortest(s, t) + dual[s] - dual[t]) +
// (shortest(s, v) + dual[s] - dual[v]) = - shortest(s,
// t) + dual[t] + shortest(s, v) = shortest(s, v) -
// shortest(s, t) >= 0 - (n-1)C
dual_dist[v].first -= dual_dist[t].second - dual_dist[v].second;
}
return true;
};
Cap flow = 0;
Cost cost = 0, prev_cost_per_flow = -1;
std::vector<std::pair<Cap, Cost>> result = {{Cap(0), Cost(0)}};
while (flow < flow_limit) {
if (!dual_ref()) break;
Cap c = flow_limit - flow;
for (int v = t; v != s; v = g.elist[prev_e[v]].to) {
c = std::min(c, g.elist[g.elist[prev_e[v]].rev].cap);
}
for (int v = t; v != s; v = g.elist[prev_e[v]].to) {
auto& e = g.elist[prev_e[v]];
e.cap += c;
g.elist[e.rev].cap -= c;
}
Cost d = -dual_dist[s].first;
flow += c;
cost += c * d;
if (prev_cost_per_flow == d) {
result.pop_back();
}
result.push_back({flow, cost});
prev_cost_per_flow = d;
}
return result;
}
};

} // namespace atcoder
#define int long long
inline int read(){int x=0,f=1;char ch=getchar();
while(ch<'0'||ch>'9'){if(ch=='-')f=-1;
ch=getchar();}while(ch>='0'&&ch<='9'){x=(x<<1)+
(x<<3)+(ch^48);ch=getchar();}return x*f;}
#define Z(x) (x)*(x)
#define pb push_back
#define fi first
#define se second
//#define M
//#define mo
int n, m, i, j, k, T, C;

namespace Sol1 {
#define N 10010
int x, y, d[N], mid, ans;
void Main() {
for(i = 1; i <= n; ++i) {
x = read(); y = read();
d[i] = y - x;
if(x & 1) d[i] = -d[i];
}
sort(d + 1, d + n + 1);
mid = (n + 1) >> 1; k = -d[mid];
for(i = 1; i <= n; ++i) d[i] += k;
for(i = 1; i <= n; ++i) ans += abs(d[i]);
printf("%lld", ans);
}
#undef N
}

namespace Sol2 {
#define N 50
int ans = 1e18, sum, mid;
int b[N], a[N], us[N], x, y;
vector<int>G[N];
int Mod(int k) {
return (k % (2 * C) + 2 * C) % (2 * C);
}
int suan(vector<int>&h, int k) {
int sum = 0;
for(auto t : h) sum += abs(t - k);
return sum;
}
void check() {
for(i = 0; i < 2 * C; ++i) {
k = a[i] * 2 - i + 1; k = Mod(k);
if(a[k] != Mod(a[i] + C)) return ;
}
// for(i = 0; i < 2 * C; ++i) debug("%lld ", a[i]); debug("\n");
for(i = sum = 0; i < 2 * C; ++i) {
if(i & 1) continue;
vector<int>h;
k = a[i] * 2 - i + 1; k = Mod(k);
for(auto t : G[i]) h.pb(a[i] + t);
for(auto t : G[k]) h.pb(a[i] + t + C);
if(h.empty()) continue;
sort(h.begin(), h.end()); m = h.size(); mid = (m + 1) >> 1; --mid;
j = h[mid]; j /= C;
sum += min(suan(h, j * C), suan(h, (j + 1) * C));
// for(auto t : h) debug("%lld ", t); debug("\n");
// for(auto t : h) sum += abs(t + j);
if(sum > ans) return ;
}
// debug(">> %lld\n", sum);
ans = min(ans, sum);
}
void dfs(int x) {
if(x >= 2 * C) {
check();
return ;
}
for(int i = 0; i < 2 * C; ++i) {
a[x] = i;
dfs(x + 1);
}
}
void Main() {
for(i = 1; i <= n; ++i) {
x = read(); y = read();
k = (x % (2 * C) + (2 * C)) % (2 * C);
G[k].pb(x - k - y);
}
for(i = 0; i < 2 * C; ++i, debug("\n"))
for(auto t : G[i]) debug("%lld ", t);
dfs(0);
printf("%lld", ans);
}
#undef N
}

namespace Sol3 {
int ans, a1, mid, x, y, S;
vector<int> G[610];
int Mod(int k) {
return (k % (2 * C) + 2 * C) % (2 * C);
}
int suan(vector<int>&h, int k) {
int sum = 0;
for(auto t : h) sum += abs(k - t);
return sum;
}
int calc(int i, int j) {
vector<int>h;
a1 = (i + j - 1) / 2; a1 = Mod(a1);
for(auto t : G[i]) h.pb(t);
for(auto t : G[j]) h.pb(- j - i + 1 - t - C);
for(auto &t : h) t = -t;
sort(h.begin(), h.end()); m = h.size(); mid = (m + 1) >> 1; --mid;
if(h.empty()) return 0;
// for(auto t : h) debug("%lld ", t);
// if(a1 == 0) a1 = 2 * C;
int p = h[mid] / C;
// debug("|| %lld | %lld %lld\n", p, p * C, (p + 1) * C); 、
int ans = 1e18;
for(int i = -5; i <= 5; ++i) ans = min(ans, suan(h, (p + i) * C + a1));
return ans;
// return min({suan(h, p * C), suan(h, (p + 1) * C, suan(h, (p - 1) * C)});
}
void Main() {
for(i = 1; i <= n; ++i) {
x = read(); y = read();
k = (x % (2 * C) + (2 * C)) % (2 * C);
G[k].pb(x - k - y);
}
atcoder :: mcf_graph<int, int>G(2 * C + 10);
S = 2 * C; T = S + 1;
for(i = 0; i < 2 * C; i += 2) G.add_edge(S, i, 1, 0);
for(i = 1; i < 2 * C; i += 2) G.add_edge(i, T, 1, 0);

for(i = 0; i < 2 * C; i += 2)
for(j = 1; j < 2 * C; j += 2) {
// G.add_edge(i, j, 1, min(calc(i, j), calc(j, i)));
G.add_edge(i, j, 1, calc(i, j));
debug("%lld <-> %lld ===> %lld\n", i, j, calc(i, j));
}
auto t = G.flow(S, T);
debug("%lld ", t.fi);
printf("%lld", t.se);
}
}

signed main()
{
freopen("function.in", "r", stdin);
freopen("function.out", "w", stdout);
// srand(time(NULL));
// T=read();
// while(T--) {
//
// }
n = read(); C = read();
// if(n <= 4 && C <= 4) return Sol2 :: Main(), 0;
// if(C == 1) return Sol1 :: Main(), 0;
// if(n == 1) return printf("0"), 0;
Sol3 :: Main();
return 0;
}