本文搬运自本人初中博客园博客,若图片加载不出来,可到原文查看:https://www.cnblogs.com/zhangtingxi/p/15633892.html

题目链接

由于 n15n\leqslant 15,所以我们可以直接枚举每条题目选或不选,最后判断是否合法即可。

时间复杂度:O(2n)O(2^n)

Code

1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
// Problem: CF550B Preparing Olympiad
// Contest: Luogu
// URL: https://www.luogu.com.cn/problem/CF550B
// Memory Limit: 250 MB
// Time Limit: 2000 ms
//
// Powered by CP Editor (https://cpeditor.org)

#include<bits/stdc++.h>
using namespace std;
#define int long long
inline int read(){int x=0,f=1;char ch=getchar();
while(ch<'0'||ch>'9'){if(ch=='-')f=-1;
ch=getchar();}while(ch>='0'&&ch<='9'){x=(x<<1)+
(x<<3)+(ch^48);ch=getchar();}return x*f;}
//#define mo
//#define M
//#define M
int n, m, i, j, k;
int a[20], l, r, kx, ans;

void dfs(int x, int sum, int mn, int mx)
{
if(x>n)
{
if(sum>=l&&sum<=r)
if(mx-mn>=kx) ++ans;
return ;
}
dfs(x+1, sum, mn, mx);
dfs(x+1, sum+a[x], min(mn, a[x]), max(mx, a[x]));
}

signed main()
{
// freopen("tiaoshi.in","r",stdin);
// freopen("tiaoshi.out","w",stdout);
n=read(); l=read(); r=read(); kx=read();
for(i=1; i<=n; ++i) a[i]=read();
dfs(1, 0, 1000001, 0);
printf("%lld", ans);
return 0;
}